Corner shapes L+1 shape ‐ Practical 1 question
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|Squared||It's about the shape in the audio lecture (at 10.15) with no outside liberties compared to the same shape with 3 outside liberties (5.43). They're both at move 19.
In the lecture Guo Juan explains that with outside liberties, white's corner is alive. Without outside liberties it becomes a ko. I can completely see this when the number of outside liberties is equal to 3. I can also see it when the number of outside liberties equals 2. But it seems to me that with 1 outside liberty, it also becomes a ko? I cannot figure out how to get unconditional life for white, if white still has 1 outside liberty. Can you please explain when black plays at S1 when white has 1 outside liberty (not 3)? Thanks.
|kvasir||If I understand which position you mean, then I think white can play S2 after S1 and that will not be a ko because after black T4, white R1, black T2, then white can still play T3 because of the extra liberty.|
|Darrell Malick||It's a good question Squared. The answer is that with one outside liberty, White should get at least seki. Guo Juan is adding a couple problems to the set to address your question. I'll let you know when they're online.|
|Darrell Malick||Ok! There are four new problems added to the set to fully answer your question. :-)|
|Squared||Great! Thanks, for the quick response. I'll go check them out right away ;-)|
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